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=6V^2-30V-36
We move all terms to the left:
-(6V^2-30V-36)=0
We get rid of parentheses
-6V^2+30V+36=0
a = -6; b = 30; c = +36;
Δ = b2-4ac
Δ = 302-4·(-6)·36
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-42}{2*-6}=\frac{-72}{-12} =+6 $$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+42}{2*-6}=\frac{12}{-12} =-1 $
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